When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\]

latex
s=vt [latex]E=mc^2[/latex] [latex] t=t_{1}-t_{2}[/latex] [latex] t=\frac{s}{v}[/latex] [katex] t=\frac{s}{v} [/katex]
[latex] t=t_{1}-t_{2}[/latex]
  • [latex] t=t_{1}-t_{2}[/latex]
  • [latex]E=mc^2[/latex]
 
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latex

s=vt [latex]E=mc^2[/latex] [latex] t=t_{1}-t_{2}[/latex] [latex] t=\frac{s}{v}[/latex] [katex] t=\frac{s}{v} [/katex]

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